From Test-Scratch-Wiki

With Scratch 2.0's time 橢圓形積木 capabilities, displaying the time or creating a 字串 of the current time is possible. However, using the (目前時間的 [分 v]) block displays a 24-hour clock, excluding "a.m." and "p.m.", and also has other disabilities. This tutorial shows how to properly display the time to one's liking as an alternative to joining the basic time capabilities provided by the 目前時間的 () block.


One of the issues with the current () block is that minutes and seconds are not zero-padded, meaning they do not have a "0" before single-digit values. For example, time may be displayed realistically as:

1:04:07 p.m.

Meaning it is 1 hour, 4 minutes, and 7 seconds past 12:00 p.m. However, joining the strings together, Scratch would normally display the time as:


To work around this, 變量s can be used to designate the realistically correct value for each time unit, and then they can be joined together as a string. To fix the 24 hour issue, one can add -12 to the hour if it reaches a certain time. For the following script, assume:

  • (hour) is the variable used to display the current hour
  • (minute) is the variable used to display the current minute
  • (second) is the variable used to display the current second
  • (half) is the variable used to display if the time is before or after 12:00 p.m.
  • (time) is the variable used to display the united time

In the script below, for example, if you do not want to include "seconds" or any other time unit, the instances of it as well as related blocks must be removed

定義 separate (string) into words
變數 [letter# v] 設為 (1) // this variable will represent an individual letter in "string"
刪除第 [全部 v] 項 \( [words v] \) // clears all the words
新增項目 [] \( [words v] \) // adds a blank item as the basis for the first word
重複 (字串長度\( (string) \)) 次 
  如果 <(字串中第 (letter#) 字\( (string) \)) = [ ]> 那麼 
    新增項目 [] \( [words v] \) // adds a new, blank item to the list if the current letter is a space
    替換第 (last v) 項於 [words v] 成 (字串組合 (清單第 (last v) 項項目\( [words v] \) :: list) 和 (字串中第 (letter#) 字\( (string) \))) // adds the letter to the current word
  end // note that a space is inserted into this string, not nothing
  變數 [letter# v] 改變 (1) // moves on to the next letter
end // repeats the amount of letters in the string
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